Bulletin Boards - Thread: Status session

By 11Drago (684)
On 17 Aug 2011 20:26

Hi,I made a status for my site and all I need to do now is echo the username session,but when I do it,it doesn't work I would like to see an example of what I do to see what I did wrong.

...

By PasserByGuy (268)
On 17 Aug 2011 21:18

Are you trying to print the correct session?
Is the session_start() function used and BEFORE the <html> tag?

Does this alter-ego make me look stupid?

By 11Drago (684)
On 17 Aug 2011 21:21

Yes.

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By Skittles (1292)
On 17 Aug 2011 23:08

Just do this:

<?php
session_start();
$var=$_SESSION[whatever];
echo "$var";
?>
That's all you have to do. o.o

It's my job to help the next generation, and set a good example for them. And for that I'll gladly lay down my life.

By PasserByGuy (268)
On 17 Aug 2011 23:31

Or just do:
<?
session_start();
echo($_SESSION[whatever]);
?>

Does this alter-ego make me look stupid?

By Skittles (1292)
On 18 Aug 2011 00:14

@PasserbyGuy That too. xD

@11drago If you show us your code, it's much easier for us to spot the error.

It's my job to help the next generation, and set a good example for them. And for that I'll gladly lay down my life.

By 11Drago (684)
On 18 Aug 2011 01:29

I did everything you did above,there were NO errors.

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By 11Drago (684)
On 18 Aug 2011 01:31

The script was like
<?php
session_start();
?>
BLAHBLAHBLAHBLAH
<?php
(Some stuff here)
echo "$session";
?>

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By PasserByGuy (268)
On 18 Aug 2011 02:13

Did you even declare the variable "$session"?

Does this alter-ego make me look stupid?

By 11Drago (684)
On 18 Aug 2011 13:59

Yes.

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By Skittles (1292)
On 18 Aug 2011 15:32

It's $_session not $session.

Just show us the entire file. Like I said, it's much easier to determine what you're doing wrong if we can actually see the code.

It's my job to help the next generation, and set a good example for them. And for that I'll gladly lay down my life.

By 11Drago (684)
On 18 Aug 2011 15:36

$_session is in the variable.

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By Skittles (1292)
On 18 Aug 2011 19:42

Can you please just show us the whole file?

It's my job to help the next generation, and set a good example for them. And for that I'll gladly lay down my life.

By PasserByGuy (268)
On 18 Aug 2011 21:06

Terry-
He means $_SESSION[whatever]=$session.

Does this alter-ego make me look stupid?

By Akshay (125)
On 18 Aug 2011 21:23

....

-- Akshay

By 11Drago (684)
On 18 Aug 2011 21:23

The script is.
<?php
session_start();
?>
some html
<?php
include("connect.php");
$session=$_SESSION['username'];
if($_POST['submit'])
{
(skipped to inserting)
$sql="INSERT INTO status(Msg)VALUES('".$_POST['msg']."')";
$query=mysql_query($sql);
}
?>

...

By 11Drago (684)
On 18 Aug 2011 21:27

The script continued.
<?php
$sql2="SELECT * FROM status";
$result=mysql_query($sql2);
while($row=mysql_fetch_array($result))
{
echo "$session";
echo "<br>";
echo $row['Msg'];
}
?>

...

By Skittles (1292)
On 19 Aug 2011 18:46

What exactly happens when you try to echo the $session variable?
I think I see the problems with your file.
Try something like this:

<?php
session_start();
include 'connect.php';
$session=$_SESSION[username];
?>
[[Some html]]

Also, you should set up so that the data inserts the current user's name with each post, otherwise your status will display every post as having been made by the person viewing the page.
Set your form up like this:

<form method="post" action="">
<textarea name="msg" value="" rows="4" cols="15" type="text"></textarea>
<input type="submit" name="submit" value="Post"/>
</form>

(Also, use isset for form submission:)

<?php
//get user info
$stuff="SELECT username FROM user WHERE username='$session'";
$stuff=mysql_fetch_array($stuff);
$user=$stuff[username];

if(isset($_POST[submit])){
//You need to sanitize user input like this
$msg=mysql_real_escape_string($_POST[msg]);
$name=$user;
$sql=mysql_query("INSERT INTO status(Msg, username)VALUES($msg, $name)");
}
$sql2="SELECT * FROM status";
$res=mysql_query($sql2);
while($row=mysql_fetch_array($res))
{
$username=$row[username]
//You only need to use 1 echo statement here, 3 is unneeded
echo "
$name
</br>
$row[Msg]
";
}
?>

That should work, though I probably made a syntax error somewhere. I tried to keep queries and stuff as simple as possible, such as the query to gather user information.

It's my job to help the next generation, and set a good example for them. And for that I'll gladly lay down my life.

By MetalHeart (1172)
On 19 Aug 2011 23:55

A status doesn't take long to make.

.

By 11Drago (684)
On 21 Aug 2011 05:04

Ok,thanks skittles.I'll try it.

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