Bulletin Boards - Thread: Getting A Dew Errors???

By Limxzero (5329)
On 03 Sep 2011 13:36

I know very little about PHP overall, but my guesses would be that it's with the if-else structure and the echo statement. Try using curly braces ("{ }") in the if-else like:

if (condition)
{
statements;
}
else
{
statements;
}

And the echo, if you're trying to output that string, it might have to be:

echo "Not";

Again, do take this with a grain of salt.

Catch my drift.

By PasserByGuy (268)
On 03 Sep 2011 16:31

For arrays, you use [ and ], not { and }.
When making an argument, it goes like this:
if($variable1==$variable2){
//my code here
}

Be sure to close if statements with }. That's the main reason why you're getting an unexpected else error:
Because an if statement must be properly written first to accompany the else.
Like <html> goes with </html>.
Starting and closing.
Ying and yang.

There's no ; after an if statement.

We've all grown up. Cheers.

By Limxzero (5329)
On 03 Sep 2011 16:52

[repost]
Yes. A semicolon almost universally ends the "line" of code and proceeds to the next unbraced statement. When you place one at the end of a condition, the expression is evaluated, but nothing is done based on it. Obviously that defeats the purpose of checking the condition, so you don't want that.

Catch my drift.

By Sevas34 (286)
On 03 Sep 2011 18:50

Go on PHP.net.

Hi there! I've returned!

By PasserByGuy (268)
On 04 Sep 2011 00:08

Show us the whole script, please.

We've all grown up. Cheers.

By PasserByGuy (268)
On 04 Sep 2011 01:31

You already typed in a { for the if statement.
You close it with }.
/facepalm

Are you dyslexic or something? o.-

We've all grown up. Cheers.

By Limxzero (5329)
On 04 Sep 2011 01:33

For one, your if-else syntax is still wrong. Should be:

if (condition) {
//statements to execute if true
}
else {
//statements to execute if false
}

Catch my drift.

By PasserByGuy (268)
On 04 Sep 2011 03:27

It has nothing to do with your connection.
You are merely just not assigning a value to either $username or $password.

You see, when you do something like if($variable), the if statement basically checks to see if:
1. The variable exists.
2. The variable has a value.

If $username or $password don't follow the above guidlines, the if statement will return FALSE, and your else statement will be run as an error code.

We've all grown up. Cheers.

By M.J kInG (1331)
On 04 Sep 2011 21:33

Where you have
$username =$_POST{username};
and
$password =$_POST{password};

change that to $username = $_POST[username]; $password =$_POST[password];

And other error like passer said you did not assigned the value for username and password.

A true developer